(d) In high spin octahedral complexes, oct is less than the electron pairing energy, and is relatively very small. A complex can be classified as high spin or low spin. DING DING DING! WE HAVE A WINNER! Thanks for A2A!!! You should learn the spectrochemical series to know which are weak field ligands and which are strong field ligands. The terms high spin and low spin are related to coordination complexes. Spin states when describing transition metal coordination complexes refers to the potential spin configurations of the central metal's d electrons. The configuration of CoF 6 3– is. Chemistry MCQs for Class 12 Chapter Wise with Answers PDF Download was Prepared Based on Latest Exam Pattern. [F (H[Fe(H O) ]3+ ihihi ith 5 i d l t It h ti t f 2 6 3+ ions are high-spin with 5 unpaired electrons. When talking about all the molecular geometries, we compare the crystal field splitting energy (Δ) and the pairing energy (P). The high-spin octahedral complex has a total spin state of +2 (all unpaired d electrons), while a low spin octahedral complex has a total spin state of +1 (one set of paired d electrons, two unpaired). Ligands for which ∆ o < P are known as weak field ligands and form high spin complexes. In many these spin states vary between high-spin and low-spin configurations. It has a magnetic moment of 6 B.M. Answer: usually produce low spin complexes and high crystal field splittings 9 (Crystal Field Theory) Which one of the following statements is FALSE? 3) With manganese, a high spin and a low spin octahedral complex are actually different. These are called spin states of complexes. The key difference between high spin and low spin complexes is that high spin complexes contain unpaired electrons, whereas low spin complexes tend to contain paired electrons.. A In an octahedral crystal field, the d electrons on a metal ion occupy the eg set of orbitals before they occupy the t2g set of orbitals BINGO! The unpaired electrons in the d-orbitals do not tent to pair up because F – is weak ligand. 16. We can determine these states using crystal field theory and ligand field theory. Explanation: Co exists as Co 3+ in [CoF 6] 3–.The configuration of. (c) Low spin complexes can be paramagnetic. (e) Low spin complexes contain strong field ligands. The formation of complex depend on the crystal field splitting, ∆ o and pairing energy (P). i)If ∆ o < P, the fourth electron enters one of the eg orbitals giving theconfiguration t 2g 3. (Ligands which cause a … Free PDF Download of CBSE Chemistry Multiple Choice Questions for Class 12 with Answers Chapter 9 Coordination Compounds. It just categorizes, qualitatively, how the metal d orbitals are filled in crystal field theory after they are split by what the theory proposes are the ligand-induced electron repulsions. Correct option (c) [CoF 6] 3– . Students can solve NCERT Class 12 Chemistry Coordination Compounds MCQs Pdf with Answers to know their preparation level. All we have to do is compare the energy it takes to pair electrons with the energy it takes to excite an electron to the higher energy (e g) orbitals. Weak field ligands: I- , Br- , SCN- , Cl- , F- , OH- , NO2- , H2O. Examples of low-spin d^6 complexes are ["Cr"("CN")_6]^(3-) and "Cr"("CO")_6, and examples of high-spin d^6 complexes are ["CrCl"_6]^(3-) and "Cr"("H"_2"O")_6. The choice between high-spin and low-spin configurations for octahedral d 4, d 5, d 6, or d 7 complexes is easy. If it takes less energy to pair the electrons, the complex is low-spin. The usual Hund's rule and Aufbau Principle apply. 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